JEE Main 2019 — Inverse Trigonometric Functions Question with Solution
From: JEE Main 2019 (Online) 10th April Evening Slot
Question
If ,where –1 x 1, – 2 y 2, x
, then for all x, y, 4x2
– 4xy cos + y2
is equal
to :
Choose an option
Show full solutionCorrect option: A
Correct answer
A4 sin2
Step-by-step explanation
squaring both sides
4x2 – 4xy cos + y2 = 4
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This is a previous-year question from JEE Main 2019, covering the Inverse Trigonometric Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.