JEE Main 2021MathematicsIndefinite IntegrationMediumNumerical

JEE Main 2021 — Indefinite Integration Question with Solution

JEE Main 2021 (18 Mar Shift 1)

Question

If fx=∫5x8+7x6x2+1+2x72dx, x≥0, f0=0 and f1=1K, then the value of K is

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Show full solutionCorrect answer: 4
Correct answer
4

Step-by-step explanation

fx=∫5x8+7x6dxx14x-5+x-7+22

Let x-5+x-7+2=t

-5x-6-7x-8dx=dt

⇒fx=∫-dtt2=1t+c

fx=x7x2+1+2x7

f1=14

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About this question

This is a previous-year question from JEE Main 2021, covering the Indefinite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.