JEE Main 2019MathematicsIndefinite IntegrationMediumMCQ

JEE Main 2019 — Indefinite Integration Question with Solution

JEE Main 2019 (09 Apr Shift 1)

Question

∫sec2x·cot43xdx is equal to

Choose an option

Show full solutionCorrect option: C
Correct answer
C-3tan-13x+C

Step-by-step explanation

Given integral can be written as

I=∫sec2xtanx43 dx

Let tanx=t

⇒sec2xdx=dt

⇒I=∫t-43 dt

Using ∫xndx=xn+1n+1+C, we get

I=t-13-13+ C

  ⇒I=-3t13+ C

⇒I=-3tan-13x+C.

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About this question

This is a previous-year question from JEE Main 2019, covering the Indefinite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.