JEE Main 2024 — Indefinite Integration Question with Solution
JEE Main 2024 (06 Apr Shift 2)
Question
If constant, then the maximum value of , is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
$\begin{aligned}
& \int \frac{\sec ^2 x d x}{a^2 \tan ^2 x+b^2} \\
& \text { let } \tan x=t \\
& \sec ^2 d x=d t \\
& \int \frac{d t}{a^2 t^2+b^2} \\
& \frac{1}{a^2} \int \frac{d t}{t^2+\left(\frac{b}{a}\right)^2} \\
& \frac{1}{a^2} \frac{1}{\frac{b}{a}} \tan ^{-1}\left(\frac{t}{b} a\right)+c \\
& \frac{1}{a b} \tan ^{-1}\left(\frac{\alpha}{b} \tan x\right)+c
\end{aligned}$
on comparing
$\begin{aligned}
& a b=12 \\
& a=6, b=2
\end{aligned}$
maximum value of
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This is a previous-year question from JEE Main 2024, covering the Indefinite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.