JEE Main 2020 — Hyperbola Question with Solution
From: JEE Main 2020 (Online) 8th January Evening Slot
Question
If a hyperbola passes through the point
P(10, 16) and it has vertices at (± 6, 0), then the
equation of the normal to it at P is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A2x + 5y = 100
Step-by-step explanation
Let hyperbola is
vertices (a, 0 ) = (6, 0) a = 6
Hyperbola passes through p(10, 16)
b = 12
Required hyperbola is
Equation of normal will be
At P(10,16) normal is
18x + 45y = 900
2x + 5y = 100
vertices (a, 0 ) = (6, 0) a = 6
Hyperbola passes through p(10, 16)
b = 12
Required hyperbola is
Equation of normal will be
At P(10,16) normal is
18x + 45y = 900
2x + 5y = 100
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Hyperbola chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Hyperbola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.