JEE Main 2019 — Hyperbola Question with Solution
From: JEE Main 2019 (Online) 8th April Evening Slot
Question
If the eccentricity of the standard hyperbola
passing through the point (4,6) is 2, then the
equation of the tangent to the hyperbola at (4,6)
is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A2x – y – 2 = 0
Step-by-step explanation
Formula for standard hyperbola :
It passes through (4, 6)
........(1)
We know,
4 = [ as e = 2 ]
....(2)
Putting in equation (1)
,
So Equation of hyperbola is
Equation of tangent to the hyperbola at (4, 6) is
2x – y – 2 = 0
It passes through (4, 6)
........(1)
We know,
4 = [ as e = 2 ]
....(2)
Putting in equation (1)
,
So Equation of hyperbola is
Equation of tangent to the hyperbola at (4, 6) is
2x – y – 2 = 0
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This is a previous-year question from JEE Main 2019, covering the Hyperbola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.