JEE Main 2024 — Hyperbola Question with Solution
From: JEE Main 2024 (Online) 8th April Evening Shift
Question
Let be the focus of the hyperbola , on the positive -axis. Let be the circle with its centre at and passing through the point . If is the origin and is a diameter of , then the square of the area of the triangle OSB is equal to __________.
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Show full solutionCorrect answer: 40
Step-by-step explanation
is mid-point of
\Delta (OSB) = \left| {{1 \over 2}\left| {\matrix{ 0 & 0 & 1 \cr {2\sqrt 2 } & 0 & 1 \cr {2\sqrt 6 - 2\sqrt 2 } & {2\sqrt 5 } & 1 \cr } } \right|} \right| = 2\sqrt {10}<./p>
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