JEE Main 2020 — Hyperbola Question with Solution
From: JEE Main 2020 (Online) 2nd September Evening Slot
Question
For some , if the eccentricity of the
hyperbola, x2–y2sec2 = 10 is times the
eccentricity of the ellipse, x2sec2 + y2 = 5, then the length of the latus rectum of the ellipse, is :
hyperbola, x2–y2sec2 = 10 is times the
eccentricity of the ellipse, x2sec2 + y2 = 5, then the length of the latus rectum of the ellipse, is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Given equation of hyperbola
Hence eccentricity of hyperbola
...(i)
Now equation of ellipse
Hence eccenticity of ellipse
...(ii)
given
Hence
Squaring both sides
...(iii)
Now length of latus rectum of ellipse =
Hence eccentricity of hyperbola
...(i)
Now equation of ellipse
Hence eccenticity of ellipse
...(ii)
given
Hence
Squaring both sides
...(iii)
Now length of latus rectum of ellipse =
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Hyperbola chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Hyperbola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.