JEE Main 2017 — Hyperbola Question with Solution
From: JEE Main 2017 (Online) 8th April Morning Slot
Question
The locus of the point of intersection of the straight lines,
tx 2y 3t = 0
x 2ty + 3 = 0 (t R), is :
tx 2y 3t = 0
x 2ty + 3 = 0 (t R), is :
Choose an option
Show full solutionCorrect option: D
Correct answer
Da hyperbola with the length of conjugate axis 3
Step-by-step explanation
Here, tx 2y 3t = 0 & x 2ty + 3 = 0
On solving, we get;
y = = & x =
Put t = tan
x = 3 sec 2 & 2y = 3 ( tan 2)
sec22 tan22 = 1
= 1
which represents at hyperbola
a2 = 9 & b2 = 9/4
(T.A.) = 6; e2 = 1 + = 1 + e =
On solving, we get;
y = = & x =
Put t = tan
x = 3 sec 2 & 2y = 3 ( tan 2)
sec22 tan22 = 1
= 1
which represents at hyperbola
a2 = 9 & b2 = 9/4
(T.A.) = 6; e2 = 1 + = 1 + e =
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This is a previous-year question from JEE Main 2017, covering the Hyperbola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.