JEE Main 2021MathematicsFunctionsMediumMCQ

JEE Main 2021 — Functions Question with Solution

JEE Main 2021 (25 Jul Shift 2)

Question

If x be the greatest integer less than or equal to x, then  ∑n=8100-1nn2 is equal to:

Choose an option

Show full solutionCorrect option: B
Correct answer
B4

Step-by-step explanation

Let S= ∑n=8100-1n·n2

Therefore, S=4-5+5-6+6+…-50+50

⇒S=4.

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About this question

This is a previous-year question from JEE Main 2021, covering the Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.