JEE Main 2012 — Ellipse Question with Solution
JEE Main 2012 (19 May Online)
Question
If the foci of the ellipse coincide with the foci of the hyperbola , then is equal to
Choose an option
Show full solutionCorrect option: C
Correct answer
C7
Step-by-step explanation
Given equation of ellipse is
Equation of hyperbola is
Since, foci of ellipse and hyperbola coincide
& \therefore \pm 4 \sqrt{1-\frac{b^2}{16}}=\pm 3 \Rightarrow b^2=7 \\
$$
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This is a previous-year question from JEE Main 2012, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.