JEE Main 2022MathematicsEllipseEasyMCQ

JEE Main 2022 — Ellipse Question with Solution

JEE Main 2022 (25 Jul Shift 2)

Question

If the ellipse x2a2+y2b2=1 meets the line x7+y26=1 on the x-axis and the line x7-y26=1 on the y-axis, then the eccentricity of the ellipse is

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Show full solutionCorrect option: A
Correct answer
A57

Step-by-step explanation

Given,

x2a2+y2b2=1 meets the line x7+y26=1 on the x-axis, so at x-axis y=0 putting in both equation and comparing we get, a=7 

And x2a2+y2b2=1 meets the line x7-y26=1 on the y-axis where x=0 so putting in both equation and comparing we get, b=26

Therefore, e2=1-b2a2=1-2449

⇒e=2549=57

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About this question

This is a previous-year question from JEE Main 2022, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.