JEE Main 2013MathematicsEllipseHardMCQ

JEE Main 2013Ellipse Question with Solution

JEE Main 2013 (07 Apr)

Question

The equation of the circle passing through the foci of the ellipse x216+y29=1, and having centre at 0,3 is

Choose an option

Show full solutionCorrect option: C
Correct answer
Cx2+y2-6y-7=0

Step-by-step explanation

For x216+y29=1

ae=16-9=7

Foci=±7,0

Radius=7+9=4

Equation of circle=x-02+y-32=42

x2+y2-6y-7=0

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Ellipse chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2013, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.