JEE Main 2021 — Ellipse Question with Solution
From: JEE Main 2021 (Online) 27th August Morning Shift
Question
If x2 + 9y2 4x + 3 = 0, x, y R, then x and y respectively lie in the intervals :
Choose an option
Show full solutionCorrect option: D
Correct answer
D[1, 3] and
Step-by-step explanation
x2 + 9y2 4x + 3 = 0
(x2 4x) + (9y2) + 3 = 0
(x2 4x + 4) + (9y2) + 3 4 = 0
(x 2)2 + (3y)2 = 1
(equation of an ellipse).
As it is equation of an ellipse, x & y can vary inside the ellipse.
So, and
x [1, 3]
(x2 4x) + (9y2) + 3 = 0
(x2 4x + 4) + (9y2) + 3 4 = 0
(x 2)2 + (3y)2 = 1
(equation of an ellipse).
As it is equation of an ellipse, x & y can vary inside the ellipse.
So, and
x [1, 3]
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This is a previous-year question from JEE Main 2021, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.