JEE Main 2021 — Ellipse Question with Solution
From: JEE Main 2021 (Online) 27th July Evening Shift
Question
Let E be an ellipse whose axes are parallel to the co-ordinates axes, having its center at (3, 4), one focus at (4, 4) and one vertex at (5, 4). If mx y = 4, m > 0 is a tangent to the ellipse E, then the value of 5m2 is equal to _____________.
Enter your answer
Show full solutionCorrect answer: 3
Correct answer
3
Step-by-step explanation
Given C(3, 4), S(4, 4)
and A(5, 4)
Hence, a = 2 & ae = 1
e =
b2 = 3
So,
Intersecting with given tangent.
Now, D = 0 (as it is tngent)
So, 5m2 = 3.
and A(5, 4)
Hence, a = 2 & ae = 1
e =
b2 = 3
So,
Intersecting with given tangent.
Now, D = 0 (as it is tngent)
So, 5m2 = 3.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Ellipse chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.