JEE Main 2019 — Differentiation Question with Solution
From: JEE Main 2019 (Online) 11th January Morning Slot
Question
If xloge(logex) x2 + y2 = 4(y > 0), then at x = e is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Differentiating with respect to x,
at we get
as
at we get
as
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This is a previous-year question from JEE Main 2019, covering the Differentiation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.