JEE Main 2017MathematicsDifferentiationHardMCQ

JEE Main 2017 — Differentiation Question with Solution

JEE Main 2017 (08 Apr Online)

Question

If y=x+x2-115+x-x2-115, then x2-1d2ydx2+xdydx is equal to

Choose an option

Show full solutionCorrect option: C
Correct answer
C225 y

Step-by-step explanation

y=x+x2-115+x-x2-115

dydx=15x+x2-1141+xx2-1+15x-x2-1141-xx2-1

dydx=15x+x2-114x+x2-1x2-1+15x-x2-114x-x2-1x2-1

dydx=15x+x2-115-x-x2-115x2-1

⇒ x2-1 .dydx=15x+x2-115-x-x2-115

⇒ xx2-1 .dydx+ x2-1d2ydx2=15×15yx2-1

⇒ xdydx+x2-1d2y dx2=15x2-1×15yx2-1=225y

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About this question

This is a previous-year question from JEE Main 2017, covering the Differentiation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.