JEE Main 2020 — Differential Equations Question with Solution
From: JEE Main 2020 (Online) 9th January Morning Slot
Question
If for x 0, y = y(x) is the solution of the
differential equation
(x + 1)dy = ((x + 1)2 + y – 3)dx, y(2) = 0, then y(3) is equal to _______.
(x + 1)dy = ((x + 1)2 + y – 3)dx, y(2) = 0, then y(3) is equal to _______.
Enter your answer
Show full solutionCorrect answer: 3
Correct answer
3
Step-by-step explanation
(x + 1)dy = ((x + 1)2 + y – 3)dx
(1 + x) - y = (1 + x)2 - 3
I.F = =
Solution of the differential equation,
=
=
= x + + C
As y(2) = 0 x = 2, y = 0
0 = 2 + + C
C = -3
So solution is = x + - 3
y(3) means x = 3 and find value of y.
y = 3
(1 + x) - y = (1 + x)2 - 3
I.F = =
Solution of the differential equation,
=
=
= x + + C
As y(2) = 0 x = 2, y = 0
0 = 2 + + C
C = -3
So solution is = x + - 3
y(3) means x = 3 and find value of y.
y = 3
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