JEE Main 2020 — Differential Equations Question with Solution
From: JEE Main 2020 (Online) 3rd September Evening Slot
Question
If x3dy + xy dx = x2dy + 2y dx; y(2) = e and
x > 1, then y(4) is equal to :
x > 1, then y(4) is equal to :
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
=
Where A = 1, B = +2, C = 1
As
Now put x = 4 in equation
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This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.