JEE Main 2020MathematicsDifferential EquationsMediumMCQ

JEE Main 2020 — Differential Equations Question with Solution

JEE Main 2020 (04 Sep Shift 2)

Question

The solution of the differential equation dydx-y+3xloge(y+3x)+3=0 is
(where C is a constant of integration)

Choose an option

Show full solutionCorrect option: A
Correct answer
Ax-12loge(y+3x)2=C

Step-by-step explanation

  dydx-y+3xln(y+3x)+3=0
dydx+3=y+3xln(y+3x)
ddx(y+3x)=y+3xln(y+3x)
∫ln(y+3x)(y+3x)d(y+3x)=∫dx
Let ln(y+3x)=t
1(y+3x)d(y+3x)=dt
∫tdt=∫dx
t22=x+c
(ln(y+3x))22=x+c

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About this question

This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.