JEE Main 2019 — Differential Equations Question with Solution
From: JEE Main 2019 (Online) 10th April Morning Slot
Question
If y = y(x) is the solution of the differential equation
, ,
such that y (0) = 0, then is equal to :
, ,
such that y (0) = 0, then is equal to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
This is linear differential equation
Now solution is
Let tanx = t
sec2xdx = dt
yetanx = tet – et + c
yetanx = (tanx – 1)etanx + c
y = (tanx – 1) + c · e–tanx
Given y(0) = 0
0 = –1 + c c = 1
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This is a previous-year question from JEE Main 2019, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.