JEE Main 2019 — Differential Equations Question with Solution
From: JEE Main 2019 (Online) 9th January Morning Slot
Question
If y = y(x) is the solution of the differential equation,
x + 2y = x2, satisfying y(1) = 1, then y() is equal to :
x + 2y = x2, satisfying y(1) = 1, then y() is equal to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Given,
This is a linear differential equation.
I.F
Solution is,
given
Equation is
means
y =
This is a linear differential equation.
I.F
Solution is,
given
Equation is
means
y =
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This is a previous-year question from JEE Main 2019, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.