JEE Main 2020 — Definite Integration Question with Solution
From: JEE Main 2020 (Online) 7th January Evening Slot
Question
If 1
and 2
be respectively the smallest and the largest values of in (0, 2) - {} which satisfy
the equation,
2cot2 - + 4 = 0, then
is equal to :
2cot2 - + 4 = 0, then
is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
2cot2 - + 4 = 0
= 0
2sin2 – 5sin + 2 = 0
(2sin – 1)(sin – 2) = 0
sin = [ sin = 2 not possible]
1 = and 2 = as 1 2
I =
=
=
=
= 0
2sin2 – 5sin + 2 = 0
(2sin – 1)(sin – 2) = 0
sin = [ sin = 2 not possible]
1 = and 2 = as 1 2
I =
=
=
=
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