JEE Main 2020 — Definite Integration Question with Solution
From: JEE Main 2020 (Online) 3rd September Evening Slot
Question
Suppose f(x) is a polynomial of degree four,
having critical points at –1, 0, 1. If
T = {x R | f(x) = f(0)}, then the sum of squares of all the elements of T is :
T = {x R | f(x) = f(0)}, then the sum of squares of all the elements of T is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D4
Step-by-step explanation
Critical points = 1, 0, 1.
f'(x) = a(x 1)(x + 1)x
f(x) = a
f(x) = f(0)
x = 0, ,
T =
Sum of square of elements of
f'(x) = a(x 1)(x + 1)x
f(x) = a
f(x) = f(0)
x = 0, ,
T =
Sum of square of elements of
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