JEE Main 2019 — Definite Integration Question with Solution
From: JEE Main 2019 (Online) 10th January Evening Slot
Question
If f(t) dt = x2 + t2f(t) dt then f ' is -
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
f(t) dt = x2 + t2f(t) dt f ' = ?
Differentiate w.r.t. 'x'
f(x) = 2x + 0 x2 f(x)
f(x) = f '(x) =
f '(x) =
f '
Differentiate w.r.t. 'x'
f(x) = 2x + 0 x2 f(x)
f(x) = f '(x) =
f '(x) =
f '
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Definite Integration chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2019, covering the Definite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.