JEE Main 2015MathematicsDefinite IntegrationMediumMCQ

JEE Main 2015 — Definite Integration Question with Solution

JEE Main 2015 (04 Apr)

Question

The integral ∫24logx2logx2+log6-x2dx is equal to

Choose an option

Show full solutionCorrect option: D
Correct answer
D1

Step-by-step explanation

I=∫24logx2logx2+log6-x2dx

I=∫24log6-x2log6-x2+logx2dx

∵∫abfxdx=∫abfa+b-xdx

2I=∫24logx2+log6-x2log6-x2+logx2dx

2I=∫241dx

2I=x24

∴  I=1

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About this question

This is a previous-year question from JEE Main 2015, covering the Definite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.