JEE Main 2021 — Definite Integration Question with Solution
From: JEE Main 2021 (Online) 26th February Morning Shift
Question
The value of the integral is ___________.
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Show full solutionCorrect answer: 2
Correct answer
2
Step-by-step explanation
$\begin{aligned} & \text { Let } I=\int_0^\pi|\sin 2 x| d x
\\\\ & =2 \int_0^{\pi / 2}|\sin 2 x| d x \quad[\because \sin 2 x \text { is periodic function }]
\\\\ & =2 \int_0^{\pi / 2} \sin 2 x \,d x[\sin 2 x \text { is positive in range }(0, \pi / 2)]
\\\\ & =2\left[\frac{-\cos 2 x}{2}\right]_0^{\pi / 2} \\\\ & =-[\cos \pi-\cos 0]=-(-1-1)=2 \end{aligned}$
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This is a previous-year question from JEE Main 2021, covering the Definite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.