JEE Main 2026MathematicsComplex NumberMediumMCQ

JEE Main 2026Complex Number Question with Solution

JEE Main 2026 (05 April Shift 2)

Question

Let be the distinct solutions of the equation . Then is equal to :

Choose an option

Show full solutionCorrect option: D
Correct answer
D

Step-by-step explanation

Given equation is

Let the roots be and .

Sum of roots:

Product of roots:

We know that



Taking modulus on both sides:



Using the parallelogram law for complex numbers:











Answer:

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About this question

This is a previous-year question from JEE Main 2026, covering the Complex Number chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.