JEE Main 2021 — Circle Question with Solution
From: JEE Main 2021 (Online) 16th March Evening Shift
Question
Let the lengths of intercepts on x-axis and y-axis made by the circle
x2 + y2 + ax + 2ay + c = 0, (a < 0) be 2 and 2, respectively. Then the shortest distance from origin to a tangent to this circle which is perpendicular to the line x + 2y = 0, is equal to :
x2 + y2 + ax + 2ay + c = 0, (a < 0) be 2 and 2, respectively. Then the shortest distance from origin to a tangent to this circle which is perpendicular to the line x + 2y = 0, is equal to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
.... (1)
.... (2)
(Given a < 0)
Equation of circle
Equation of tangent which is perpendicular to the line x + 2y = 0 is
p = r
Tangent
Distance from origin =
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