JEE Main 2025 — Circle Question with Solution
JEE Main 2025 (28 Jan Shift 1)
Question
Let the equation of the circle, which touches -axis at the point and cuts off an intercept of length on -axis be . If the circle lies below -axis, then the ordered pair is equal to
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
By pythagoras Equation of circle is comparision $\begin{array}{r} -\alpha=-2 a, \beta=-2 p, r=a^2 \\ \Rightarrow 2 a=\alpha, 4 a^2+b^2=4 p^2 \\ \alpha^2+b^2=4 p^2 \\ \alpha^2+b^2=\beta^2 \end{array}$ So,
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Circle chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2025, covering the Circle chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.