JEE Main 2022MathematicsCircleEasyMCQ

JEE Main 2022 — Circle Question with Solution

JEE Main 2022 (28 Jul Shift 2)

Question

Let the tangents at two points A and B on the circle x2+y2-4x+3=0 meet at origin O0,0. Then the area of the triangle of OAB is

Choose an option

Show full solutionCorrect option: B
Correct answer
B334

Step-by-step explanation

Given the tangents at two points A and B on the circle x2+y2-4x+3=0 meet at origin O0,0,

Plotting the diagram we get,

 

Now circle C:x-22+y2=1

Equation of chord AB is given by T=0 i.e x×0+y×0-4x+02+3=0

⇒AB:2x=3

Now OA=OB=02+02-4×0+3=3

So, AM=OA2-OM2=3-94=34=32

Now area of triangle OAB=122AMOM

=334 sq. units

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About this question

This is a previous-year question from JEE Main 2022, covering the Circle chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.