JEE Main 2019MathematicsCircleMediumMCQ

JEE Main 2019 — Circle Question with Solution

JEE Main 2019 (12 Apr Shift 2)

Question

A circle touching the x- axis at (3, 0) and making an intercept of length 8 on the y- axis passes through the point:

Choose an option

Show full solutionCorrect option: A
Correct answer
A3, 10 

Step-by-step explanation


Since circle touches the x-axis at 3, 0, hence centre can be taken as 3,α and radius =α
Since y-intercept is 8, by applying Pythagorean theorem
32+42=α2⇒α=5,-5
Hence two circles are possible
x-32+y-52=25  and x-32+y+52=25.
Clearly (3, 10) satisfies the given equation of circle.

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About this question

This is a previous-year question from JEE Main 2019, covering the Circle chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.