JEE Main 2025 — Circle Question with Solution
JEE Main 2025 (23 Jan Shift 1)
Question
Let the arc of a circle subtend a right angle at the centre . If the point on the arc , divides the arc such that , and , then is equal to
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
(2) Now $\begin{aligned} & \alpha+\sqrt{2}(\sqrt{3}-1) \beta=\frac{-(\sqrt{3}+1)}{(\sqrt{3}-1)}+\frac{\sqrt{2}(\sqrt{3}-1) \cdot 2 \sqrt{2}}{\sqrt{3}-1} \\ & =\frac{-(\sqrt{3}+1)^2}{2}+4 \\ & =\frac{-3-1-2 \sqrt{3}+8}{2} \\ & =2-\sqrt{3} \end{aligned}$
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This is a previous-year question from JEE Main 2025, covering the Circle chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.