JEE Main 2019 — Binomial Theorem Question with Solution
From: JEE Main 2019 (Online) 10th April Evening Slot
Question
The smallest natural number n, such that the coefficient of x in the expansion of is nC23, is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C38
Step-by-step explanation
General term
Coefficient of x =
2n - 1 = 115 n = 58
and n = 38
smallest n = 38
Coefficient of x =
2n - 1 = 115 n = 58
and n = 38
smallest n = 38
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This is a previous-year question from JEE Main 2019, covering the Binomial Theorem chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.