JEE Main 2022MathematicsBinomial TheoremMediumMCQ

JEE Main 2022Binomial Theorem Question with Solution

JEE Main 2022 (25 Jul Shift 2)

Question

The remainder when 111011+101111 is divided by 9 is _____ .

Choose an option

Show full solutionCorrect option: B
Correct answer
B8

Step-by-step explanation

111011=113327=9k+8327

when divided by 9 is equivalent to the division of 

8327=9-1327

i.e. remainder=-1+9=8

Now, 101111=9m+311

when divided by 9 is equivalent to the division of 

311=95×3

i.e. remainder=0

   111011+101111 has same remainder as 8.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Binomial Theorem chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Binomial Theorem chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.