JEE Main 2015MathematicsArea Under CurvesMediumMCQ

JEE Main 2015 — Area Under Curves Question with Solution

JEE Main 2015 (10 Apr Online)

Question

The area (in square units) of the region bounded by the curves y+2x2=0 and y+3x2=1, is equal to

Choose an option

Show full solutionCorrect option: D
Correct answer
D43 sq. units

Step-by-step explanation

To find point of intersection of two given curves

Put y=-2x2 in y+3x2=1

⇒ x2=1

⇒ x=±1

Let the given equations be y1=1-3x2 and y2=-2x2.

The desired area would be,

∫-11y1-y2dx =∫-111-3x2--2x2dx

=∫-111-x2dx

=x- x33-11= 1-13- -1+13

=23- -23

=43 sq. units .

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About this question

This is a previous-year question from JEE Main 2015, covering the Area Under Curves chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.