JEE Main 2020MathematicsArea Under CurvesMediumMCQ

JEE Main 2020 — Area Under Curves Question with Solution

JEE Main 2020 (03 Sep Shift 1)

Question

The area (in sq. units) of the region x, y:0≤y≤x2+1, 0≤y≤x+1, 12≤x≤2 is

Choose an option

Show full solutionCorrect option: B
Correct answer
B7924

Step-by-step explanation

0≤y≤x2+1, 0≤y≤x+1, 12≤x≤2

Drawing the graph according to the given information,

Area is, A=∫121x2+1dx+∫12x+1dx

A=x33+x121+x22+x12

A=13+1-123·13+12+42+2-12+1

A=43-124+12+2+2-32

A=43-1324+4-32

A=32-13+96-3624

A=7924 sq. units.

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About this question

This is a previous-year question from JEE Main 2020, covering the Area Under Curves chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.