JEE Main 2020MathematicsArea Under CurvesMediumMCQ

JEE Main 2020Area Under Curves Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

The area (in sq. units) of the region x,yR2:x2y3-2x, is.

Choose an option

Show full solutionCorrect option: A
Correct answer
A323

Step-by-step explanation

Point of intersection of y=x2 & y=-2x+3, is obtained by x2+2x-3=0x=-3,1.

So, area of the required region is

-313-2x-x2 dx

=3x-x2-x33-31=323.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Area Under Curves chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Area Under Curves chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.