JEE Main 2020MathematicsArea Under CurvesMediumMCQ

JEE Main 2020 — Area Under Curves Question with Solution

JEE Main 2020 (07 Jan Shift 2)

Question

The area (in sq. units) of the region x,y∈R24x2≤y≤8x+12 is

Choose an option

Show full solutionCorrect option: B
Correct answer
B1283

Step-by-step explanation

4x2=y
y=8x+12
4x2=8x+12
x2-2x-3=0
x=-1,3
A=∫-138x+12-4x2dx
A=8x22+12x-4x333-1=49+36-36-4-12+43=36+8-43
=44-43=132-43=1283

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About this question

This is a previous-year question from JEE Main 2020, covering the Area Under Curves chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.