JEE Main 2020 — Application Of Derivatives Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
Let P(h, k) be a point on the curve
y = x2 + 7x + 2, nearest to the line, y = 3x – 3.
Then the equation of the normal to the curve at P is :
y = x2 + 7x + 2, nearest to the line, y = 3x – 3.
Then the equation of the normal to the curve at P is :
Choose an option
Show full solutionCorrect option: D
Correct answer
Dx + 3y + 26 = 0
Step-by-step explanation
Let L be the common normal to parabola
y = x2 + 7x + 2 and line y = 3x – 3
Slope of tangent of y = x2 + 7x + 2 at P
= 3
2x + 7 = 3
x = -2
y = -8
So P(–2, –8)
Normal at P : x + 3y + C = 0
-2 + 3(-8) + C = 0
C = 26
Normal : x + 3y + 26 = 0
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