JEE Main 2020 — Application Of Derivatives Question with Solution
From: JEE Main 2020 (Online) 5th September Evening Slot
Question
Which of the following points lies on the
tangent to the curve
x4ey + 2 = 3 at the point (1, 0)?
x4ey + 2 = 3 at the point (1, 0)?
Choose an option
Show full solutionCorrect option: D
Correct answer
D(–2, 6)
Step-by-step explanation
x4ey + 2 = 3
Differentiating w.r.t. x, we get
x4eyy' + ey4x3 + = 0
At P(1, 0)
+ 4 + = 0
= -2
Tangent at P(1, 0) is
y – 0 = – 2 (x – 1)
2x + y = 2
Only (–2, 6) lies on it.
Differentiating w.r.t. x, we get
x4eyy' + ey4x3 + = 0
At P(1, 0)
+ 4 + = 0
= -2
Tangent at P(1, 0) is
y – 0 = – 2 (x – 1)
2x + y = 2
Only (–2, 6) lies on it.
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