JEE Main 2019 — Application Of Derivatives Question with Solution
From: JEE Main 2019 (Online) 8th April Evening Slot
Question
Given that the slope of the tangent to a curve y
= y(x) at any point (x, y) is
. If the curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0, then its equation is :
Choose an option
Show full solutionCorrect option: A
Correct answer
Ax loge|y| = 2(x – 1)
Step-by-step explanation
Slope, =
....... (1)
Center of the circle x2 + y2 – 2x – 2y = 0 is (1, 1)
Equation (1) passes through point (1, 1)
0 = -2 + C
C = 2
x
x
....... (1)
Center of the circle x2 + y2 – 2x – 2y = 0 is (1, 1)
Equation (1) passes through point (1, 1)
0 = -2 + C
C = 2
x
x
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