JEE Main 2017MathematicsApplication of DerivativesMediumMCQ

JEE Main 2017 — Application of Derivatives Question with Solution

JEE Main 2017 (02 Apr)

Question

The normal to the curve  yx-2 x-3=x+6 at the point where the curve intersects the y-axis passes through the point:

Choose an option

Show full solutionCorrect option: B
Correct answer
B12,12

Step-by-step explanation

To find the point where curve intersects the y-axis 

Put, x=0, we get

 6y=6⇒y=1

Hence, the point is (0, 1).

On differentiating

⇒dydx x-2 x-3+y2x-5=1

Put, x=0, y=1, we get

⇒ dydx+6+1-5=1

⇒dydx=1

⇒ Slope of normal =-1

Equation of normal at 0, 1

⇒y-1=-1x-0

⇒x+y-1=0

Point 12,12 satisfy the normal.

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About this question

This is a previous-year question from JEE Main 2017, covering the Application of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.