JEE Main 2016 — Application Of Derivatives Question with Solution
From: JEE Main 2016 (Online) 9th April Morning Slot
Question
The minimum distance of a point on the curve y = x2−4 from the origin is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Let point on the curve
y = x2 4 is (2, 2 4)
Distance of the point (2, 2 4) from origin,
D =
D2 = 2 + 4 + 16 82
4 72 + 16
= 43 14
Now, = 0
43 14 = 0
2 (22 7) = 0
= 0 or 2 =
Distance is minimum at 2 =
Minimum distance
D =
=
y = x2 4 is (2, 2 4)
Distance of the point (2, 2 4) from origin,
D =
D2 = 2 + 4 + 16 82
4 72 + 16
= 43 14
Now, = 0
43 14 = 0
2 (22 7) = 0
= 0 or 2 =
Distance is minimum at 2 =
Minimum distance
D =
=
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