JEE Main 2020MathematicsApplication Of DerivativesRate Of Change Of QuantitymediumMCQ

JEE Main 2020Application Of Derivatives Question with Solution

From: JEE Main 2020 (Online) 9th January Morning Slot

Question

A spherical iron ball of 10 cm radius is coated with a layer of ice of uniform thickness the melts at a rate of 50 cm3/min. When the thickness of ice is 5 cm, then the rate (in cm/min.) at which of the thickness of ice decreases, is :

Choose an option

Show full solutionCorrect option: A
Correct answer
A

Step-by-step explanation

Let the thickness = h cm

Volume of ice = v =



Given 50 cm3/min and h = 5 cm

50 =

= cm/min

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About this question

This is a previous-year question from JEE Main 2020, covering the Application Of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.