JEE Main 2020 — Application Of Derivatives Question with Solution
From: JEE Main 2020 (Online) 9th January Morning Slot
Question
A spherical iron ball of 10 cm radius is
coated with a layer of ice of uniform
thickness the melts at a rate of 50 cm3/min.
When the thickness of ice is 5 cm, then the rate
(in cm/min.) at which of the thickness of ice
decreases, is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Let the thickness = h cm
Volume of ice = v =
Given 50 cm3/min and h = 5 cm
50 =
= cm/min
Volume of ice = v =
Given 50 cm3/min and h = 5 cm
50 =
= cm/min
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This is a previous-year question from JEE Main 2020, covering the Application Of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.