JEE Main 2020 — Application Of Derivatives Question with Solution
From: JEE Main 2020 (Online) 6th September Evening Slot
Question
If the tangent to the curve, y = f (x) = xloge x,
(x > 0) at a point (c, f(c)) is parallel to the line-segment
joining the points (1, 0) and (e, e), then c is equal to :
(x > 0) at a point (c, f(c)) is parallel to the line-segment
joining the points (1, 0) and (e, e), then c is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
y = f (x) = xloge x
1 + loge x
= 1 + loge e = m1
This tangent parallel to the line-segment
joining the points (1, 0) and (e, e).
Slope of line-segment joining the points (1, 0) and (e, e) = m1
= 1 + loge e
loge e = - 1 =
c =
1 + loge x
= 1 + loge e = m1
This tangent parallel to the line-segment
joining the points (1, 0) and (e, e).
Slope of line-segment joining the points (1, 0) and (e, e) = m1
= 1 + loge e
loge e = - 1 =
c =
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