JEE Main 2020MathematicsApplication Of DerivativesTangent And NormalmediumNumerical

JEE Main 2020Application Of Derivatives Question with Solution

From: JEE Main 2020 (Online) 5th September Evening Slot

Question

If the lines x + y = a and x – y = b touch the
curve y = x2 – 3x + 2 at the points where the curve intersects the x-axis, then is equal to _______.

Enter your answer

Show full solutionCorrect answer: 0.5
Correct answer
0.5

Step-by-step explanation

y = x2 – 3x + 2

y = (x – 1)(x – 2)

At x-axis y = 0
x = 1, 2

So this curve intersects the x-axis at A(1, 0) and B(2, 0).



and

Equation of tangent at A(1, 0) :

y = –1(x –1)

x + y = 1

and equation of tangent at B(2, 0):

y = 1(x – 2)

x – y = 2

So a = 1 and b = 2

= 0.5

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About this question

This is a previous-year question from JEE Main 2020, covering the Application Of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.