JEE Main 2019 — Application Of Derivatives Question with Solution
From: JEE Main 2019 (Online) 12th April Morning Slot
Question
A 2 m ladder leans against a vertical wall. If the top of the ladder begins to slide down the wall at the rate
25 cm/sec, then the rate (in cm/sec.) at which the bottom of the ladder slides away from the wall on the
horizontal ground when the top of the ladder is 1 m above the ground is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
x2 + y2 = 4
When upper end is 1m above the ground, cm/sec.
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This is a previous-year question from JEE Main 2019, covering the Application Of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.