JEE Main 2016MathematicsApplication of DerivativesEasyMCQ

JEE Main 2016 — Application of Derivatives Question with Solution

JEE Main 2016 (09 Apr Online)

Question

The minimum distance of a point on the curve y=x2-4 from the origin is 

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Show full solutionCorrect option: A
Correct answer
A152 units

Step-by-step explanation

A variable point on the given parabola can be taken as α, α2-4



Distance from origin D= α2+α2-42

⇒ D2=α2+α4+16-8α2

=α4-7α2+16

dD2dα=4α3-14 α=0

⇒ 2α2α2-7=0

⇒ α=0, 72, -72



∴ Dmin 2 at α2=72

Dmin2=494-492+16

= -494+16=154

Dmin=152

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About this question

This is a previous-year question from JEE Main 2016, covering the Application of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.