JEE Main 2017MathematicsApplication of DerivativesEasyMCQ

JEE Main 2017 — Application of Derivatives Question with Solution

JEE Main 2017 (09 Apr Online)

Question

The function f defined by fx=x3-3x2+5x+7 is:

Choose an option

Show full solutionCorrect option: B
Correct answer
BIncreasing in R

Step-by-step explanation

We have fx=x3-3x2+5x+7

f′x=3x2-6x+5>0      

D=b2-4ac=36-4·3·5=-14 -ve

Then, f'x>0. 

Hence, fx is increasing in R. 

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About this question

This is a previous-year question from JEE Main 2017, covering the Application of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.